Homework Statement
The magnitude of the gravitational force exerted by the Earth on an object of mass m at the Earth's surface is
Fg = G*M*m/ R^2
where M and R are the mass and radius of the Earth.
Let's say the object is instead a height y << R above the surface of the Earth. Using a...
Homework Statement
In a cathode ray tube (CRT) used in older television sets and oscilloscopes, a beam of electrons is steered to different placed on a phosphor screen, which glows at locations hit by electrons. The CRT is evacuated, so there are few gas molecules present for the electrons to...
Homework Statement
A steel ball of mass m falls from a height h onto a scale calibrated in newtons. The ball rebounds repeatedly to nearly the same height h. The scale is sluggish in its response to the intermittent collisions and displays an average force Favg, such that FavgT = FΔt, where...
Okay, thanks for that tip. I used the distance formula sqrt((x2-x1)^2+(y2-y1)^2+(z2-z1)^2) equals distance.
I got r = 8.25E10m
I then plugged it into the equation for gravitational force. F= GM1M2/r^2
I got Fg=1.72E29
Then using this force I did p(final)-p(initial) = Fg delta(t) for each...
First I used Newtons gravitational force equation. Fg= GM1M2/r^2
M1=5E30 kg is given
M2 = 3.5E30 kg is given
G = 6.66E-11
Calculated R by using pythagorean theory for both coordinates and adding together
I got R =1.14E13
Then using the force calculated I used the momentum principle...
At t = 0 a star of mass 5.0×1030 kg has velocity < 6.0×10^4, 7.0×10^4, -7.0×10^4 > m/s and is located at < 1.00×10^12, -4.00×10^12, 4.00×10^12 > m relative to the center of a cluster of stars. There is only one nearby star that exerts a significant force on the first star. The mass of the second...